I think you need to try some lighter-roasted, higher-quality beans which were roasted fairly recently and only grind them a day or so before you use them. There are also different brewing methods and coffee/water ratios that you can try.
I love and consume lots of coffee but I sincerely believe it only tastes good because I associate the taste with the boost it gives. Exactly like cigarettes taste tolerable, good even, when you smoke them regularly.
If you don’t know what you’re drinking, it’s probably dark roast. Dark roast is like charcoal compared to light roast.
The coffee most folks use (i.e. Folgers, Maxwell House) is low-quality coffee made in haste to keep the price low enough for folks to be willing to buy it. They only offer darker roasts because disguise the inferior nature of the beans, or rather the inferior process. The unfortunate truth is that good coffee costs more to process because it takes longer to process and most folks don’t want to spend that much on coffee. So, you get what you pay for.
I wish, companies just expect you to write garbage code as quick as possible, only to create tens of bugs afterwards that will take way more time than it would if they had left you enough time to do it correctly
Java has many abstractions that can be beneficial in certain circumstances. However, it forces a design principle that may not work best in every situation.
I.e. inheritance can be both unnatural for the programmer to think in, and is not representative of how data is stored and manipulated on a computer.
You don’t have to use inheritance with Java. In fact, in most cases it’s better that you don’t. Practically all of the Java standard library doesn’t require the use of inheritance, same with most modern libraries.
On the contrary, I think inheritance is a very natural way to think. However, that doesn’t translate into readable and easy to maintain code in the vast majority of the cases.
I am not sure what you mean by how it’s stored or manipulated on a computer. A garbage collected language like Java manages the memory for you. It doesn’t really care if your code is using inheritance or not. And unless you’re trying to squeeze the last drops of performance out of your code, the memory layout shouldn’t be on your mind.
People hating on Java because “inheritance” usually don’t know the difference between inheritance and polymorphism. Stuff like composition and dependency inversion is black magic to them.
We’re gate-keeping the most mainstream programming language now? Next you’ll say English isn’t a real language because it doesn’t have a native verb tense to express hearsay.
And it is not forced at all. Noone holds a gun to your head to write extends. “Favor composition over inheritance” has been said as a mantra for at least a decade
Memory is an implementation detail. You are interested in solving problems, not pushing bytes around, unless that is the problem itself. In 99% of the cases though, you don’t need guns and knives, it’s not a US. school (sorry)
I do not like Java but this is a strange argument. The people that invented Java felt that most of the C language should be wrapped in unsafe.
Opinions can vary but saying Java is not a real language is evidence free name calling. One could just as easily say that any language that does not allow you to differentiate between safe and unsafe baheviour is incomplete and not a “real” language. It is not just the Java and C# people that may say this. As a C fan, I am sure you have heard Rust people scoff at C as a legacy language that was fine for its day but clearly outclassed now that the “real” languages have arrived. Are you any more correct than they are?
Yeah it makes sense to me. You can always cast it if you want an int that bad. Hell just wrap the whole function with your own if it means that much to you
How does that work? Is it just because double uses more bits? I’d imagine for the same number of bits, you can store more ints than doubles (assuming you want the ints to be exact values).
No, I get that. I’m sure the programming language design people know what they are doing. I just can’t grasp how a double (which has to use at least 1 bit to represent whether or not there is a fractional component) can possibly store more exact integer vales than an integer type of the same length (same number of bits).
It just seems to violate some law of information theory to my novice mind.
I’m going to guess here (cause I feel this community is for learning)…
Integers have exactness. Doubles have range.
So if MAX_INT + 1 is possible, then ~(MAX_INT + 1) is probably preferable to an overflow or silent MIN_INT.
But Math.ceil probably expects a float, because it is dealing with decimals (or similar). If it was an int, rounding wouldn’t be required.
So if Math.ceil returned and integer, then it could parse a float larger than INT_MAX, which would overflow an int (so error, or overflow). Or just return a float
I don’t think that’s possible. Representing more exact ints means representing larger ints and vice versa. I’m ignoring signed vs. unsigned here as in theory both the double and int/long can be signed or unsigned.
Edit: ok, I take this back. I guess you can represent larger values as long as you are ok that they will be estimates. Ie, double of N (for some very large N) will equal double of N + 1.
I would need to look into the exact difference of double vs integer to know, but a partially educated guess is that they are referring to Int32 vs double and not Int64, aka long. I did a small search and saw that double uses 32 bits for the whole numbers and the others for the decimal.
Okay, so I dug in a bit deeper. Doubles are standardized as a 64 bit bundle that is divided into 1 signed bit, 11 exponetioal bits and 52 bits for decimal. It’s quite interesting. As to how it works indepth, I probably will try to analyze a bit conversion if I can try something
You can think of a double as having a fixed precision, but, in contrast to an integer, this precision can be moved over the decimal point depending on the value you want to represent. Therefore, despite representing floating-point numbers, a double still has discrete steps determined by its binary representation of 64 bits. If the value of a double gets larger, it reaches a point where the smallest difference between two subsequent doubles is greater than one. For float (32 bit), you reach this point at 16777216. The next larger number to be represented as a float is 16777218 (i.e., +2).
I agree with all that. But I’m talking about exact integer values as mentioned in the parent.
I just think this has to be true: count(exact integers that can be represented by a N bit floating point variable) < count(exact integers that can be represented by an N bit int type variable)
It doesn’t. A double is a 64 bit value while an integer is 32 bit. A long is a 64 bit signed integer which stores more exact integer numbers than a double.
Technically, a double stores most integers exactly ( up until a certain value ) and then approximations of integers of much larger sizes. A long stores all its integers exactly but cannot handle values nearly as large.
For most real world data ranges, they are both going to store integers exactly.
Also because if you are dealing with a double, then you’re probably dealing with multiple, or doing math that may produce a double. So returning a double just saves some effort.
A double can represent numbers up to ± 1.79769313486231570x10^308, or roughly 18 with 307 zeroes behind it. You can’t fit that into a long, or even 128 bits. Even though rounding huge doubles is pointless, since only the first dozen digits or so are saved, using any kind of Integer would lead to inconsistencies, and thus potentially bugs.
Doubles have a much higher max value than ints, so if the method were to convert all doubles to ints they would not work for double values above 2^31-1.
(It would work, but any value over 2^31-1 passed to such a function would get clamped to 2^31-1)
To avoid a type conversion that might not be expected. Integer math in Java differs from floating point math.
Math.floor(10.6) / Math.floor(4.6) = 2.5 (double)
If floor returned a long, then
Math.floor(10.6) / Math.floor(4.6) = 2 (long)
If your entire code section is working with doubles, you might not like finding Math.floor() unexpectedly creating a condition for integer division and messing up your calculation. (Have fun debugging this if you’re not actively aware of this behavior).
Yeah, this grinds my gears. I use to comment my code when I'm working on my personal projects, then at the office I have to waste time trying to decipher my boss's code because he won't comment absolutely anything.
That plus the ridiculous deadlines means that I don't have time to comment my own code, fast forward several months later without working on a particular project and now I have to decipher his and my own code.
One day he actually had the nerve to say to me: 'Yeah, you should comment your code'. How I refrained of commiting murder that day I don't know.
Don't write comments for someone else. Write comments for yourself because you might write a million lines of code and then be told you need to do something to this now ancient legacy code at 3am because some nightmare scenario happens and you need to get it fixed and deployed before they'll let you go back to sleep.
programmer_humor
Oldest
This magazine is from a federated server and may be incomplete. Browse more on the original instance.