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kevincox , 10 months ago No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list. Basically the default comparator is a.sort((a, b) => ${a}<${b} ? -1 : 1).
No. It always compares by converting to string. I actually think this is more consistent then having different behaviour if you have a string somewhere in your list.
Basically the default comparator is a.sort((a, b) => ${a}<${b} ? -1 : 1).
a.sort((a, b) =>
<
? -1 : 1)