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Redkey , 3 days ago I don’t know if this will work or even compile, but I feel like I’m pretty close. <span style="color:#323232;">long main () { </span><span style="color:#323232;"> char output; </span><span style="color:#323232;"> unsigned char shift; </span><span style="color:#323232;"> long temp; </span><span style="color:#323232;"> </span><span style="color:#323232;"> if (i < 152) { </span><span style="color:#323232;"> shift = (i & 1) * 7; </span><span style="color:#323232;"> temp = b[i >> 1] >> shift; </span><span style="color:#323232;"> i++; </span><span style="color:#323232;"> output = (char)(64 & temp); </span><span style="color:#323232;"> output += (char)((n >> (temp & 63)) & main()); </span><span style="color:#323232;"> printf("%c", output); </span><span style="color:#323232;"> } </span><span style="color:#323232;"> </span><span style="color:#323232;"> return 63; </span><span style="color:#323232;">} </span>
I don’t know if this will work or even compile, but I feel like I’m pretty close.
<span style="color:#323232;">long main () { </span><span style="color:#323232;"> char output; </span><span style="color:#323232;"> unsigned char shift; </span><span style="color:#323232;"> long temp; </span><span style="color:#323232;"> </span><span style="color:#323232;"> if (i < 152) { </span><span style="color:#323232;"> shift = (i & 1) * 7; </span><span style="color:#323232;"> temp = b[i >> 1] >> shift; </span><span style="color:#323232;"> i++; </span><span style="color:#323232;"> output = (char)(64 & temp); </span><span style="color:#323232;"> output += (char)((n >> (temp & 63)) & main()); </span><span style="color:#323232;"> printf("%c", output); </span><span style="color:#323232;"> } </span><span style="color:#323232;"> </span><span style="color:#323232;"> return 63; </span><span style="color:#323232;">} </span>