small script help, action each file in a folder

12510198 , 3 months ago

What about something like this:

<span style="font-weight:bold;color:#a71d5d;">for</span><span style="color:#323232;"> i </span><span style="font-weight:bold;color:#a71d5d;">in</span><span style="color:#323232;"> /media/johann/5461-000B/DCIM/100MEDIA/</span><span style="font-weight:bold;color:#a71d5d;">*</span><span style="color:#323232;">.AVI</span><span style="font-weight:bold;color:#a71d5d;">; do </span><span style="color:#323232;">newpath</span><span style="font-weight:bold;color:#a71d5d;">=</span><span style="color:#183691;">"$</span><span style="color:#323232;">HOME</span><span style="color:#183691;">/Public/240321/$(</span><span style="color:#323232;">basename </span><span style="color:#183691;">"$</span><span style="color:#323232;">i</span><span style="color:#183691;">" </span><span style="font-weight:bold;color:#a71d5d;">| </span><span style="color:#323232;">sed </span><span style="color:#183691;">'s/^IMAG/240321_/g')"</span><span style="font-weight:bold;color:#a71d5d;">; </span><span style="color:#323232;">ffmpeg -i </span><span style="color:#183691;">"$</span><span style="color:#323232;">i</span><span style="color:#183691;">"</span><span style="color:#323232;"> -ss 00:00:00 -t 00:00:20 </span><span style="color:#183691;">"$</span><span style="color:#323232;">newpath</span><span style="color:#183691;">" </span><span style="font-weight:bold;color:#a71d5d;">&& </span><span style="color:#323232;">rm </span><span style="color:#183691;">"$</span><span style="color:#323232;">i</span><span style="color:#183691;">"</span><span style="font-weight:bold;color:#a71d5d;">; done
</span>

johsny OP , 3 months ago

Awesome! Thanks, I knew there had to be a way!

edit: This also works: for i in *.avi; do ffmpeg -i “$i” -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done

But yours is much nicer.

ClemaX , 3 months ago

Try this:

<span style="font-weight:bold;color:#a71d5d;">for</span><span style="color:#323232;"> file </span><span style="font-weight:bold;color:#a71d5d;">in</span><span style="color:#323232;"> ./</span><span style="font-weight:bold;color:#a71d5d;">*
</span><span style="font-weight:bold;color:#a71d5d;">do
</span><span style="color:#323232;">    </span><span style="color:#62a35c;">echo </span><span style="color:#183691;">"$</span><span style="color:#323232;">file</span><span style="color:#183691;">"
</span><span style="font-weight:bold;color:#a71d5d;">done
</span>

To do some substitution operation om the filename you can use Bash Parameter Expansion.

GravitySpoiled , 3 months ago

Use another folder instead of name

johsny OP , 3 months ago

The input filename changes each time.

GravitySpoiled , 3 months ago (edited 3 months ago)

<span style="color:#323232;">find -name "*.avi" | while read file;
</span><span style="color:#323232;">do
</span><span style="color:#323232;">  echo -v "$file"
</span><span style="color:#323232;">done
</span>

edited

johsny OP , 3 months ago

Almost, here is the one that worked: for i in *.avi; do ffmpeg -i “$i” -ss 00:00:00 -t 00:00:10 ~/Public/test/${i%.*}.avi ; done

Thanks for pointing me in the right direction.