Acters , 10 months ago

Every bit aside for the ones bit is even. All you have to do is get the ones bit(the far right) for it being a 1 or 0. Which is the fastest and least amount of code needed.

use bitwise &

<span style="color:#323232;">// n&amp;1 is true, then odd, or !n&amp;1 is true for even  
</span><span style="color:#323232;">
</span><span style="color:#323232;"> return (!(n &amp; 1));  
</span>