There have been multiple accounts created with the sole purpose of posting advertisement posts or replies containing unsolicited advertising.

Accounts which solely post advertisements, or persistently post them may be terminated.

This profile is from a federated server and may be incomplete. Browse more on the original instance.

liwott ,

Electrons are not subject to the strong nuclear force that glues the protons neutrons together. This means that no attractive force would prevent electric repulsion to scatter a "electron nucleus".

From a field theory perspective, the strong nuclear force is a SU(3) gauge interaction and the electron field transforms as a singlet under that SU(3)

liwott ,

Strong interaction is really designed as a baryonic thing, leptons have no color charge (which is another way to say that they transform as SU(3) singlets). Leptons do not interact with gluons.
Not at tree-level anyway. See for example https://en.wikipedia.org/wiki/Standard_Model#/media/File:Standard_Model_%E2%80%93_All_Feynman_diagram_vertices.svg.

At loop levels, it's possible to imagine an electron decaying into neutrino+W, then W into two quarks who can then interact with gluons, but as it's down a couple of orders in perturbation theory so probably much too weak to hold a nucleus together. Not an expert in particle physics so I do not know with certainty whether a couple-of-loops interaction can have a measurable effect.

  • All
  • Subscribed
  • Moderated
  • Favorites
  • •
  • random
  • lifeLocal
  • goranko
  • All magazines
    •