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KellyThomas , 1 year ago (edited 1 year ago) Meh. It’s doubling each step. If course it’s at 1/(2^n) of the final volume at n steps before the final step. At half of its final volume one step before the end a quarter of its final volume two steps before the end an eighth of its final volume three steps before the end a sixteenth of it’s final volume four steps before the end
Meh.
It’s doubling each step.
If course it’s at 1/(2^n) of the final volume at n steps before the final step.
1/(2^n)
n