d3Xt3r , 6 months ago

If you look inside the fastboot.sh file, there’s this bit of code here:

<span style="color:#323232;">command_array=($1 $2 $3 $4 $5)
</span><span style="color:#323232;">
</span><span style="color:#323232;">for command in ${command_array[*]}; do
</span><span style="color:#323232;">	case $command in
</span><span style="color:#323232;">	8917)
</span><span style="color:#323232;">        down_platform="8917"
</span><span style="color:#323232;">	continue
</span><span style="color:#323232;">	;;
</span><span style="color:#323232;">	8937)
</span><span style="color:#323232;">        down_platform="8937"
</span><span style="color:#323232;">	continue
</span><span style="color:#323232;">	;;
</span><span style="color:#323232;">esac
</span>

That means you’re supposed to pass an argument to the script with the model? number of the device. So since your device is an 8937, run the script like so: ./fastboot.sh 8937

Further down the script, you can see what it actually does: it unlocks the device, flashes a bunch of partitions and finally reboots it. Since you didn’t specify the model number, it skipped the flashing bit and went directly to the reboot bit. :)

Edit: I also took a look at the .bat files, they basically do they same thing except under Windows, and it’s specific to the model.